15u^2+18u=^3-23-8u

Solution for 15u^2+18u=^3-23-8u equation:

15u^2+18u=^3-23-8u

We move all terms to the left:

15u^2+18u-(^3-23-8u)=0

We get rid of parentheses

15u^2+18u+8u+23-^3=0

We add all the numbers together, and all the variables

15u^2+26u=0

a = 15; b = 26; c = 0;
Δ = b2-4ac
Δ = 262-4·15·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-26}{2*15}=\frac{-52}{30}
=-1+11/15
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+26}{2*15}=\frac{0}{30}
=0
$